If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x^2-5x-100=250-x^2
We move all terms to the left:
x^2-5x-100-(250-x^2)=0
We get rid of parentheses
x^2+x^2-5x-250-100=0
We add all the numbers together, and all the variables
2x^2-5x-350=0
a = 2; b = -5; c = -350;
Δ = b2-4ac
Δ = -52-4·2·(-350)
Δ = 2825
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2825}=\sqrt{25*113}=\sqrt{25}*\sqrt{113}=5\sqrt{113}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5\sqrt{113}}{2*2}=\frac{5-5\sqrt{113}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5\sqrt{113}}{2*2}=\frac{5+5\sqrt{113}}{4} $
| 12-7y=17y-5(3-4) | | m/5+6=-2 | | (7y+3)=(4y+15) | | -4-5f=-3f-10 | | 4x+10=14x+6 | | 3,1=x-1.5 | | x-3+6x=180 | | j–3=-7 | | u-66/5=5 | | 5x-(2x+4)=-10 | | 0=9-4r-7 | | x-89=-68 | | 7=3a−9.2 | | -5q+7=-4q | | 5t=35 | | 3(h-4)=24 | | 13x-3+3x+2+55=90 | | 3q+4+9=14 | | (-17)+x=-92 | | x+10=x+10= −3x+38 | | 7/3x+1/3x=10+7/3x | | -x2,x=-1 | | (-70)+x=-38 | | 8x+4+3x+4+140=90 | | -34=-3c-7 | | x-(-49)=100 | | −20=−0.4k | | 9a+2=24a-20 | | w4−1=2 | | 2(p+7)=42 | | .15(x)=300 | | 8x-15=x+25 |